Python Coding Question Solution

Python Coding Question Solution List , Tuple etc…

List Manipulation

1. Write a function that takes a list of numbers and returns a new list with each number doubled.

   def double_numbers(numbers):
       return [x * 2 for x in numbers]

   # Example usage:
   numbers = [1, 2, 3, 4, 5]
   doubled = double_numbers(numbers)
   print(doubled)  # Output: [2, 4, 6, 8, 10]

2. Create a function that takes two lists and returns a list that contains only the common elements.

   def common_elements(list1, list2):
       return list(set(list1) & set(list2))

   # Example usage:
   list1 = [1, 2, 3, 4, 5]
   list2 = [4, 5, 6, 7, 8]
   common = common_elements(list1, list2)
   print(common)  # Output: [4, 5]

Working with Tuples

1. Write a function that takes a list of tuples, each containing a name and age, and returns a list of names of people who are above 18.

   def names_above_18(people):
       return [name for name, age in people if age > 18]

   # Example usage:
   people = [("Alice", 17), ("Bob", 20), ("Charlie", 19)]
   adults = names_above_18(people)
   print(adults)  # Output: ['Bob', 'Charlie']

2. Create a function that accepts a tuple of numbers and returns a new tuple with the numbers sorted in ascending order.

   def sort_tuple(numbers):
       return tuple(sorted(numbers))

   # Example usage:
   numbers = (5, 2, 3, 1, 4)
   sorted_numbers = sort_tuple(numbers)
   print(sorted_numbers)  # Output: (1, 2, 3, 4, 5)

Set Operations

1. Write a function that takes two sets and returns their symmetric difference (elements that are in either set, but not in both).

   def symmetric_difference(set1, set2):
       return set1 ^ set2

   # Example usage:
   set1 = {1, 2, 3, 4}
   set2 = {3, 4, 5, 6}
   sym_diff = symmetric_difference(set1, set2)
   print(sym_diff)  # Output: {1, 2, 5, 6}

2. Create a function to check if one set is a subset of another.

   def is_subset(subset, superset):
       return subset <= superset

   # Example usage:
   set1 = {1, 2}
   set2 = {1, 2, 3, 4}
   result = is_subset(set1, set2)
   print(result)  # Output: True

Nested Data Structures

1. Given a list of dictionaries representing students (each dictionary containing keys like name, age, and grades), write a function to calculate the average grade of all students.

   def average_grade(students):
       total_grade = sum(student['grade'] for student in students)
       return total_grade / len(students)

   # Example usage:
   students = [
       {"name": "Alice", "age": 20, "grade": 85},
       {"name": "Bob", "age": 21, "grade": 90},
       {"name": "Charlie", "age": 19, "grade": 95}
   ]
   avg_grade = average_grade(students)
   print(avg_grade)  # Output: 90.0

2. Write a function that flattens a list of lists into a single list (e.g., [[1, 2], [3, 4]] should become [1, 2, 3, 4]).

   def flatten_list(nested_list):
       return [item for sublist in nested_list for item in sublist]

   # Example usage:
   nested_list = [[1, 2], [3, 4], [5, 6]]
   flattened = flatten_list(nested_list)
   print(flattened)  # Output: [1, 2, 3, 4, 5, 6]

These solutions demonstrate basic list, tuple, and set operations in Python, as well as handling more complex nested data structures.